TCS NQT Exam 1-Shift Coding Question | TCS NQT Exam 20/03/2026 Coding Question

Q1. Gym Membership Cost – Problem Statement

A gym offers membership plans based on the number of months a customer wants to enroll. The cost of the membership is determined as follows:

Duration (Months)	Cost (₹)
≤ 0	Invalid Input
1	2000
2 to 3	5000
4 to 6	9000
> 6	15000

Task

Write a program that:

• Takes an integer input for months
• Prints:
  • "Invalid Input" if months <= 0
  • Otherwise prints: Cost: <amount>

Input Format

• A single integer months

Output Format

• Print "Invalid Input" OR
• Print:Cost: <amount>

Sample Test Cases

Test Case 1

Input:

1

Output:

Cost: 2000

Test Case 2

Input:

3

Output:

Cost: 5000

Test Case 3

Input:

5

Output:

Cost: 9000

Test Case 4

Input:

7

Output:

Cost: 15000

Test Case 5

Input:

0

Output:

Invalid Input

Solutions

🔹 C++ Solution

#include <iostream>
using namespace std;

int main() {
    int months;
    cin >> months;

    if(months <= 0) {
        cout << "Invalid Input";
    }
    else if(months == 1) {
        cout << "Cost: 2000";
    }
    else if(months <= 3) {
        cout << "Cost: 5000";
    }
    else if(months <= 6) {
        cout << "Cost: 9000";
    }
    else {
        cout << "Cost: 15000";
    }

    return 0;
}

🔹 Java Solution

import java.util.*;

public class GymMembership {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);

        int months = sc.nextInt();

        if(months <= 0){
            System.out.println("Invalid Input");
        }
        else if(months == 1){
            System.out.println("Cost: 2000");
        }
        else if(months <= 3){
            System.out.println("Cost: 5000");
        }
        else if(months <= 6){
            System.out.println("Cost: 9000");
        }
        else{
            System.out.println("Cost: 15000");
        }
    }
}

🔹 Python Solution

months = int(input())

if months <= 0:
    print("Invalid Input")
elif months == 1:
    print("Cost: 2000")
elif months <= 3:
    print("Cost: 5000")
elif months <= 6:
    print("Cost: 9000")
else:
    print("Cost: 15000")

TCS NQT Exam 1-Shift Coding Question

Q2. Transaction Monitoring System – Problem Statement

You are building a Transaction Monitoring System for a financial platform. The system processes N transactions. Each transaction contains the following 4 parameters:

• Sender (string)
• Receiver (string)
• Timestamp (integer, in seconds)
• Amount (integer)

Rules

1. Duplicate Transaction Check

If any transaction has the same sender AND receiver as a previous transaction, print:

Error: Duplicate Transaction. Terminate the program.

2. Fraud Detection Rule

If the difference between the timestamps of any two consecutive transactions is greater than 60 seconds, print:

Fraud Detected and terminate the program.

3. Valid Case

If all transactions are valid, print: All Transactions Valid

Input Format

• First line: Integer N (number of transactions)
• Next N lines:
• Each line contains:

sender receiver timestamp amount

Output Format

Print one of the following:

• “Error: Duplicate Transaction”
• “Fraud Detected”
• “All Transactions Valid”

Constraints

• 1 ≤ N ≤ 10^5
• timestamp ≥ 0
• amount ≥ 0

Sample Test Case

Test Case 1 (Valid Transactions)

Input

3
A B 10 100
C D 50 200
E F 200 300

Output

All Transactions Valid

Test Case 2 (Duplicate Sender-Receiver)

Input:

3
A B 10 100
C D 50 200
E F 200 300

Output

Error: Duplicate Transaction

Test Case 3 (Fraud Detection)

Input:

3
A B 10 100
C D 50 200
E F 200 300

Output

Fraud Detected

Solutions

🔹 C++ Solution

#include <bits/stdc++.h>
using namespace std;

int main() {
    int N;
    cin >> N;

    set<pair<string,string>> seen;
    int prevTime = -1;

    for(int i = 0; i < N; i++) {
        string sender, receiver;
        int timestamp, amount;

        cin >> sender >> receiver >> timestamp >> amount;

        if(seen.count({sender, receiver})) {
            cout << "Error: Duplicate Transaction";
            return 0;
        }

        seen.insert({sender, receiver});

        if(prevTime != -1 && (timestamp - prevTime > 60)) {
            cout << "Fraud Detected";
            return 0;
        }

        prevTime = timestamp;
    }

    cout << "All Transactions Valid";
}
    

🔹 Java Solution

import java.util.*;

public class TransactionSystem {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);

        int N = sc.nextInt();
        Set<String> seen = new HashSet<>();

        int prevTime = -1;

        for(int i = 0; i < N; i++) {
            String sender = sc.next();
            String receiver = sc.next();
            int timestamp = sc.nextInt();
            int amount = sc.nextInt();

            String key = sender + "-" + receiver;

            if(seen.contains(key)) {
                System.out.println("Error: Duplicate Transaction");
                return;
            }

            seen.add(key);

            if(prevTime != -1 && (timestamp - prevTime > 60)) {
                System.out.println("Fraud Detected");
                return;
            }

            prevTime = timestamp;
        }

        System.out.println("All Transactions Valid");
    }
}
    

🔹 Python Solution

n = int(input())

seen = set()
prev_time = -1

for _ in range(n):
    sender, receiver, timestamp, amount = input().split()
    timestamp = int(timestamp)

    key = (sender, receiver)

    if key in seen:
        print("Error: Duplicate Transaction")
        exit()

    seen.add(key)

    if prev_time != -1 and (timestamp - prev_time > 60):
        print("Fraud Detected")
        exit()

    prev_time = timestamp

print("All Transactions Valid")
    

Join our Telegram group: Click Here

Follow us on Instagram: Click Here

Join our WhatsApp group: Click Here

More Latest Off-Campus Hiring 2025 Jobs:

• Accenture New Mass Hiring 2025 – Click Here
• Naukri Campus Hiring Drive Registration –Click Here