Accenture Previous Year Question 2024 | Cognitive , Technical, Coding

Accenture Previous Year Question 2024 : In this comprehensive post, we will delve deep into an extensive analysis of all the previous year questions from Accenture, specifically tailored for those aspiring to navigate the recruitment process in 2024. Our discussion will encompass a thorough review of the questions that have been posed in prior years, offering insights and strategies to effectively tackle each one. From technical queries to behavioral assessments, we aim to equip you with the knowledge and confidence you need to excel in your upcoming interviews. Whether you are a fresh graduate or an experienced professional seeking new opportunities, this breakdown will serve as a valuable resource in your preparation journey for joining one of the leading companies in the consulting and technology space.

Accenture Previous Year Question 2024 All Sections:

Assessment Type	Section	Number of Questions	Time (Minutes)
Cognitive Assessment	English Ability	17	90 (Shared)
	Critical Reasoning and Problem Solving	18	90 (Shared)
	Abstract Reasoning	15	90 (Shared)
Technical Assessment	Common Applications & MS Office	12	90 (Shared)
	Pseudocode	18	90 (Shared)
	Networking Security & Cloud	10	90 (Shared)
Coding Assesment	Coding and Programming Fundamentals (C, C++, .NET, Java, Python)	2	45

Accenture Previous Year Question 2024 English Ability:

Topics	Number of Questions	Difficulty	Importance
Synonyms & Antonyms	3-4	Medium	High
Error Detection / Sentence Correction	3-4	Medium	High
Para Jumbles	2	Medium	Medium
Reading Comprehension	3	High	High
Sentence Completion / Fill in the Blanks	2-3	Low	Medium
Sentence Improvement	2-3	Low	Medium

Accenture Previous Year Question 2024 Critical Reasoning and Problem Solving:

Topics	Number of Questions	Difficulty	Importance
Data Arrangements	7-8	High	High
Flow Chart	2-3	Medium	High
Data Sufficiency	1-2	Medium	Medium
Argument & Assumption	2-3	Medium	Medium
Syllogisms	2-3	Medium	Medium
Statement Conclusion	2-3	Medium	Medium

Accenture Previous Year Question 2024 Abstract Reasoning:

Topics	Number of Questions	Difficulty	Importance
Number and Letter Series	3-4	High	High
Odd Man Out	2-3	High	High
Analogies	2-3	High	High
Coding and Decoding	3-4	High	High
Visual Reasoning	4-5	Medium	Medium

Accenture Previous Year Question 2024 Common Applications & MS Office:

Topics	Number of Questions	Difficulty	Importance
MS Office (Word, PowerPoint, Excel, Outlook)	2-3	Medium	High
Browsers’ Fundamentals	2	Medium	High
Shortcut Keys	2-3	Medium	High
Command Prompt	2-3	Low	Medium
Working Flow of Keys	2	Medium	Medium

Accenture Previous Year Question 2024 Pseudocode:

Topics	Number of Questions	Difficulty	Importance
Programming Fundamentals	Part of 18 questions	High	High
Looping	Part of 18 questions	High	High
Arrays	Part of 18 questions	High	High
Recursion	Part of 18 questions	Medium	High
Function	Part of 18 questions	High	High
Bitwise Operators	Part of 18 questions	Medium	Medium
Increment & Decrement Operators	Part of 18 questions	Low	Medium
Conditional Statements	Part of 18 questions	Medium	High
Basics of Data Structures	Part of 18 questions	High	High

Accenture Previous Year Question 2024 Networl Security & Cloud:

Topics	Number of Questions	Difficulty	Importance
Basics of Networking	Among the 10 key questions	Medium	High
Network Security	Among the 10 key questions	High	High
Encryption Standards & Algorithms	Among the 10 key questions	High	High
Network Security Devices	Among the 10 key questions	High	High
Attack Types	Among the 10 key questions	High	High
Firewalls	Among the 10 key questions	Medium	Medium
Fundamentals of Cloud Computing	Among the 10 key questions	Medium	High
Client-Server Architecture	Among the 10 key questions	Medium	High
Cloud Data Centers	Among the 10 key questions	Medium	High
Cloud Service Providers	Among the 10 key questions	Medium	High
Cloud Service Platforms	Among the 10 key questions	Medium	High

Accenture Previous Year Question 2024 Coding:

Topics	Number of Questions	Difficulty	Importance
Basics of Programming	2 (45-Minute Time Limit)	High	High
Input & Output Concepts	Integrated within the primary 2 questions	High	High
Flow Control	Embedded in the core 2 questions	High	High
Conditional Looping	Part of the fundamental 2 questions	High	High
Arrays	Covered within the 2 main questions	High	High
Functions	Key topic within the 2 questions	High	High
Strings	A focus area within the 2 questions	Medium	High
Data Types & Operators	Essential part of the primary 2	Medium	High

Accenture Previous Year Question 2024 Cognitive Assesment PYQ

1. In ______ London, there are _____ great many are museums.

1. the, a
2. a, an
3. no article, a
4. the, no article

Ans: d

2. I will work _____ five o’clock.

1. until
2. up
3. in
4. to

Ans: a

3. I ______ enough money to buy a studio apartment by the end of the year.

1. will be saved
2. will have saved
3. save
4. am saved

Ans: b

4. Choose the correct synonym for the following word:
Conjecture

1. Speculate
2. Disbelieve
3. Prove
4. Deliment

Ans: a

5. Choose the correct synonym for the following word:
Curtail

1. Unfold
2. Prolong
3. Diminish
4. Maneuver

Ans: c

6. Choose the option that is opposite in meaning to the given word.
CONDUCIVE

1. Cheap
2. Usual
3. Shocking
4. Harmful

Ans: d

7. Choose the option that is opposite in meaning to the given word.
CORDONED

1. Untrue
2. Fresh
3. Free
4. Able

Ans: c

Rearrange the following phrases to form a complete sentence: Note: The phrase numbered 1 is fixed.
8. Humans store
(A) of items in short-term
(B) subsequent operations
(C) a limited number
(D) working memory to perform

1. CADB
2. BADC
3. CDBA
4. ACDB

Ans: a

9. This consists of a sentence that is either partly or entirely underlined and or may not have a grammatical error. There are four different versions of the underlined part of the sentence. Choose the option that correctly rephrases the underlined part of the following sentence. Mark the answer as ‘No error’ if there is no error in the underlined part.

The eyes of an owl gives it a wide range of “binocular vision, which means the owl can see objects in three dimensions and can judge distances in a similar way to humans.

1. The eyes of an owl give it a wide range of binocular vision, which means the owl can see objects in three dimensions and can judge distances in a similar way to humans.
2. The eyes of an owl giving it a wide range of binocular vision, which means the owl can see objects in three dimensions and can judge distances in a similar way to humans.
3. The eyes of an owl gives it a wider range of binocular vision, which means the owl can see objects in three dimensions and can judge distances in a similar way to humans.
4. The eyes of an owl have given it a wide range of binocular vision, which means the owl can see objects in three dimensions and can judge distances in a similar way to humans.
5. No error

Ans: a

10. This question consists of a sentence that is either partly or entirely underlined and may or may not have a grammatical error. There are four different versions of the underlined part of the sentence. Choose the option that correctly rephrases the underlined part of the following sentence. Mark the answer as “No error” if there is no error in the underlined part.

Make sure that you don’t left anything for tomorrow.

1. have left
2. has left
3. leave
4. leaving
5. no error

Ans: c

11. Read the following passage and answer the question given below.

Maintaining healthy soil and improving crop growth is important for farmers worldwide. Many farmers use expensive and potentially harmful chemical fertilisers, making it difficult to manage nutrients. However, scientists are exploring eco-friendly alternatives, and nanotechnology is showing game-changer.

Nano-fertilisers are tiny particles that can significantly improve how plants absorb nutrients. Regular fertilisers, nano-fertilisers release nutrients slowly, preventing them from leaching into the groundwater. This not only improves nutrient efficiency but also benefits the environment. nano-fertilisers can help crops withstand harsh conditions. When combined with microorganisms, called nano-biofertilizers, they offer even more advantages.

While nano-fertilisers offer exciting opportunities for sustainable agriculture, it is essential to be cautious. Releasing too many nanomaterials into the environment and food chain could harm human health. Therefore, it is crucial to thoroughly study and understand these potential risks before widely adopting nano fertilisers in farming Biotechnological advancements are necessary to safely and electively use nanomaterial’s in agriculture

In conclusion, nano-fertilisers have great potential for improving plant nutrition and resilience in the face of climate change. However, careful consideration and further research are necessary to ensure their safety and effectiveness in enhancing agricultural practices.

Question: What is the potential benefit of nano-fertilisers in the face of climate change?

1. They can increase the need for water in agriculture.
2. They can eliminate the need for chemical fertilisers
3. They can improve the taste and quality of crops
4. They can increase the resistance of crops to harsh condition.

Ans. d

12. Question: According to the above passage, how can nano-fertilisers benefit the environment?

1. By increasing the crop yield
2. By reducing the need for pesticides
3. By drastically altering climate change
4. By preventing nutrient from leaching into groundwater

Ans. d

13. The question has four items. Mark the one that does not belong to this group.                                                            

(a) Invoice     (b) Sales Tax      (c) Octroi       (d) Quotation

1. a
2. b
3. c
4. d

Ans: d

14. Given below are sentences which when arranged logically from a coherent passage. Choose the option which gives the correct sequence.

1. Celebrations are observed the world over, but particularly in India, by throwing colour at one another.
2. Holi celebrates the arrival of spring and summer, as the dull winter breaks into a glow of colour under clear skies.
3. For Indians, the festival is a crucial part of the year, and collecting flowers and making colours begins late in winter.
4. Perhaps because the crops sown in autumn ripen under the newly golden sun, and so anticipation of glad times becomes only natural

1. 3 2 4 1
2. 2 4 1 3
3. 2 3 4 1
4. 2 1 4 3

Ans: b

15. If V = 12R / (r + R), then R =

1. Vr/ (12V)
2. Vr + V/12
3. Vr – 12
4. V/r-12

Ans: a

16. (3x + 2) (2x – 5) = ax2 + kx + n .What is the value of a – n + k?

1. 5
2. 8
3. 9
4. 10

Ans: a

17. Statement: The government has decided to reduce the custom duty on computer peripherals

Assumptions:

I. The domestic market price of computer peripherals may go up near future

II. The domestic manufacturers may oppose the decision

1. if only I is implicit;
2. if only assumption II is implicit;
3. If either I or II is implicit;
4. if neither I nor II implicit
5. if both I and II are implicit.

Ans: d

18. Statement: It is desirable to put the child in school at the age of 5 or so.

Assumptions:

I. At that age the child reaches appropriate level of development and is ready to learn.

II. The schools do not admit children after six years of age,

1. if only I is implicit;
2. if only assumption II is implicit;
3. If either I or II is implicit;
4. if neither I nor II implicit
5. if both I and II are implicit.

Ans: a

19. Three people are sitting in a row.P1 is to the left of P3 and P2 is to the right of P1. Find the position of P3 with respect to P2.

1. Immediate left
2. Immediate right
3. Second left
4. Cannot be determined

Ans: a

20. X, Y, Z and W are sitting around a square table with each person sitting along one distinct side of the table. X sits opposite the person who is wearing a red shirt. Y sits to the immediate right of the person who wears a green shirt. The person wearing yellow is to the left of the person wearing a blue shirt. W sits on the side opposite Z. What is the colour of the shirt of X

1. Red
2. Green
3. Blue
4. Blue or Red

Ans: c

21. Believable: Credible

1. Conspire: Neglect
2. Invisible: Obvious
3. Innocent: Witty
4. Eternal: Endless

Ans: d

22. Find the missing term in the series given below.

95, 115, 155, 175, 215, ?

1. 255
2. 235
3. 240
4. 260

Ans: b

23. SHAN, BOTI, UJCP, ____

1. QVDK
2. OLVK
3. VKDQ
4. DQVK

Ans: d

24. A, H, A, L, U, ?

1. I
2. J
3. L
4. H

Ans: c

25. In ON is coded as 210, DEL is coded as 240, SJR is coded as 3420 and AT is coded as 20, what would be the code for BAT?

1. 36
2. 40
3. 88
4. None of these

Ans: b

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Accenture Previous Year Question 2024 Technical Assesment

 1. To ______ a document means to make changes to its existing content.

1. format
2. save
3. edit
4. print
5. None of these

Ans: d

2. What is the default file extension for all word documents?

1. TXT
2. DOC
3. WRD
4. FIL

Ans: b

3. Where on the MS Word screen you can locate the horizontal split bar?

1. On the vertical scroll bar’s top
2. On the vertical scroll bar’s bottom
3. The horizontal scroll bar’s left side
4. the horizontal scroll bar’s right side

Ans: a

4. .bas, .doc and .html}are example of

1. domains
2. protocols
3. database
4. extensions

Ans: d

5. What purpose do bookmarks serve?

1. To save the document in a specific location
2. To save a website’s URL for future reference
3. To use the document for search
4. To save alignments as it is.

Ans: b

6. An algorithm in encryption is called

1. Algorithm
2. Procedure
3. Cipher
4. Module

Ans: c

7. The information that gets transformed in encryption is

1. Plain text
2. Parallel text
3. Encrypted text
4. Decrypted text

Ans: a

8. Which data may not be suitable for public clouds?

1. Legacy application data
2. b. Mission-critical workloads
3. Sensitive data
4. All of the above

Ans: d

9. Which is not a form of confidential computing?

1. Trust execution environments
2. Zero-trust networks
3. Fully homomorphic encryption
4. Secure multiparty computation

Ans: b

10. When is centralized cloud application monitoring most useful?

1. When applications must span hybrid architectures
2. When applications are hosted solely in the cloud
3. When an organization’s applications are all on premises
4. When an organization uses a single cloud application

Ans: a

1. Integer p,q,r
Set p=6, q=5, r=6
p=(r+r)^q
for(each r from 4 to 5)
if(p(r-p))
q=(r^6)+r
Continue
End if
p=(q+8)&q
End for
Print p+q

Ans: 17

Initialize p = 6, q = 5, and r = 6.
Calculate p = (r + r) ^ q, resulting in p = 9.
For r values from 4 to 5, check if p < q || (p + q) > (r – p).
If true, update q = (r ^ 6) + r for each r (resulting in q = 8 after the loop).
Print p + q, which gives 17.

2. Integer pp,qq,rr
Set pp=9, qq=8, rr=8
if ((pp+rr+8)<(4+qq+pp))
if ((rr+10+qq)<(6+rr))
qq=(qq+2)+pp
Else
qq=(rr+qq)+qq
End if
Else
if ((rr+qq-pp)<(5+rr))
pp=qq+qq
End if
End if
qq=(7+4)+pp
Print pp+qq+rr;

Ans: 51

Initialize: pp = 9, qq = 8, rr = 8. 
Check if (pp + rr + 8) < (4 + qq + pp). 
(9 + 8 + 8) < (4 + 8 + 9), which is 25 < 21 (false). 
Check if (rr + qq – pp) < (5 + rr). 
(8 + 8 – 9) < (5 + 8), which is 7 < 13 (true). 
Since true, update pp = qq + qq→ pp = 8 + 8 = 16. 
Update qq = (7 + 4) + pp → qq = 11 + 16 = 27. 
Print pp + qq + rr = 16 + 27 + 8 = 51. 

3. Integer funn(Integer a, Integer b, Integer c)
b = (c^8) + c
for (each c from 4 to 7)
b = (c+11) & b
a = 11 & a
End for
return a+b

Ans: 2

Initialize: a = 2, b = 7,c = 6.
Step 2: Calculate b = (c ^ 8) + c = (6 ^ 8) + 6 = 20.
Loop (Step 3-6): For c from 4 to 7:
Iteration 1: b = (4 + 11) & 20 = 4, a = 11 & 2 = 2
Iteration 2: b = (5 + 11) & 4 = 0, a = 11 & 2 = 2
Iterations 3-4: b remains 0, a remains 2.
Return: a + b = 2 + 0 = 2.

4. Integer a,b,c
Set a=5, b=2, c=7
if ((1-c-b)>(b-a))
if (2>a)
if ((b&c)<(5-b))
a=c^a
End if
b=9+b
Else
c=11&a
End if
b=(c+3)^b
End if
c=(b+c)+b
Print a+b+c

Ans: 36

Initialize a = 5, b = 2, c = 7.
The condition ((1 – c – b) > (b – a)) evaluates to False, so we skip the nested updates for a and b.
Update b to (c + 3) ^ b, resulting in b = 8.
Update c to (b + c) + b, resulting in c = 23.
Finally, compute a + b + c = 5 + 8 + 23 = 36.

5. a=8,b=7,c=4
Integer funn(Integer a, Integer b, Integer c)
a=(b+b)&c
for(each c from 5 to 7)
b=3+c
b=(4+7)+b
a=(b&c)+c
End for
c=a+c
return a+b

Answer – 33
Initialize a = 8, b = 7, c = 4.
Update a to (b + b) & c, resulting in a = 4.
Loop through c from 5 to 7:
For c = 5: Update b to 19, then update a to 6.
For c = 6: Update b to 20, then update a to 10.
For c = 7: Update b to 21, then update a to 12.
After the loop, update c to a + c, resulting in c = 16.
Return a + b, which is 12 + 21 = 33.

Accenture Previous Year Question 2024 Coding Assesment

1. The exact output of the of the program, without any leading or preceding text or remark.
Arun is a bus conductor. His ticket machine is printing numbers in reverse order due to a technical glitch. As a programmer on the bus, you are asked to help him by creating a program to display the numbers correctly.
Example:
Input: 320
Output: Number in reverse order: 23

Input: 231
Output: Number in reverse order: 132

C++:

int reverseNumber(int num) {
int reversed = 0;
while (num > 0) {
reversed = reversed * 10 + (num % 10);
num /= 10;
}
return reversed;
}

JAVA:

int reverseNumber(int num) {
int reversed = 0;
while (num > 0) {
reversed = reversed * 10 + (num % 10);
num /= 10;
}
return reversed;
}

2. Nikhil borrowed some amount from his friend for 3 years at some rate of interest. Write a program to find simple interest
Example:
Input: 2000 50
Output: Simple interest for 3 years: 3000
Input: 10000 10
Output: Simple interest for 3 years: 3000

C++:

double calculateSI(double principal, double rate, double time) {
return (principal * rate * time) / 100;
}

JAVA:

double calculateSI(double principal, double rate, double time) {
return (principal * rate * time) / 100;
}

3. Write a function fix_case that takes a string s (1 <= |s| <= 1000) consisting of both uppercase and lowercase letters and returns the string in either all uppercase or all lowercase based on the following conditions:

• If the string s has more uppercase letters than lowercase letters, return it entirely in uppercase.
• If the string s has more lowercase letters than uppercase letters, return it entirely in lowercase.

Examples:

“AbCdEfG” == “ABCDEFG”
“xYz” == “xyz”
“ABCabcXYZ” == “abcabcxyz”

JAVA:
String convertString(String str) {
int upperCount = 0, lowerCount = 0;
for (char c : str.toCharArray()) {
if (Character.isUpperCase(c)) upperCount++;
else if (Character.isLowerCase(c)) lowerCount++;
}
if (upperCount > lowerCount) {
return str.toUpperCase();
} else {
return str.toLowerCase();
}

C++:
string convertString(string str) {
int upperCount = 0, lowerCount = 0;
for (char c : str) {
if (isupper(c)) upperCount++;
else if (islower(c)) lowerCount++;
}
if (upperCount > lowerCount) {
for (char &c : str) {
if (islower(c)) {
c = toupper(c);
}
}
} else {
for (char &c : str) {
if (isupper(c)) {
c = tolower(c);
}
}
}
return str;
}

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